Sniper work

BigRedBuster

BigRedBuster

International Man of Mystery
As someone who deer hunts so I spend some time trying to be an accurate marksman, I find this absolutely amazing and have the utmost respect for this level of skill.


 
Those are .5 MOA guns, so at that distance, he's basically hoping to be within 6 feet without accounting for wind or gravity. It's a ridiculous shot.

 
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It said that the bullet took about 10 seconds to travel from chamber to target. That is an eternity in that situation.

I would like to know how many shots like that have been attempted but missed. I'm guessing guys are trying to break the world record and taking shots like this over and over, and we're only hearing about the hits.

 
When you have to account for curvature of the earth to set up a shot you know your on another level! The technology involved in long range shooting is crazy when you think of it.

 
I'm trying to figure out the effect of the curvature of the earth. I guess gravity would pull the bullet "down" as it got closer to the target? So if you were aiming at someone's nose with no wind, you might hit their chin?

 
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zoogs said:
"At this distance, you'll also have to take the Coriolis Effect into account."
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Moiraine said:
I'm trying to figure out the effect of the curvature of the earth. I guess gravity would pull the bullet "down" as it got closer to the target? So if you were aiming at someone's nose with no wind, you might hit their chin?
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At about 10 seconds of flight time, it would be a lot more than that.

If my math is right, the distance an object would fall in 10 seconds would be 0.5*9.8m/s/s*10s^2 = 490 meters.

And to knapp's point, you'd have to be anticipating where the person would be 10 seconds after you pull the trigger. So I would that it would have to be someone standing post or sitting somewhere to even try it.

 
We're not talking about an object in freefall, though. So to model this as 2D projectile motion, you'll need to take the horizontal component into consideration (g is only relevant for the vertical component) as well. And you may want to assume air resistance.

Did the sniper actually talk about the curvature of the earth? That's so interesting. I didn't know it was this much, but I guess earth has a curvature of ~8 in/mi. Your projectile is traveling "in orbit", so to speak. g also varies by radial distance, although probably not materially over 16 inches (terrain elevation variation probably dominates...) I wonder how they distill all this modeling into intuitive guidelines for out in the field. The Coriolis effect actually seems much more relevant than curvature, and not just because Capt. MacMillan said so! I could be wrong.

 
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zoogs said:
We're not talking about an object in freefall, though. So to model this as 2D projectile motion, you'll need to take the horizontal component into consideration (g is only relevant for the vertical component) as well. And you may want to assume air resistance.

Did the sniper actually talk about the curvature of the earth? That's so interesting. I didn't know it was this much, but I guess earth has a curvature of ~8 in/mi. Your projectile is traveling "in orbit", so to speak. g also varies by radial distance, although probably not materially over 16 inches (terrain elevation variation probably dominates...) I wonder how they distill all this modeling into intuitive guidelines for out in the field. The Coriolis effect actually seems much more relevant than curvature, and not just because Capt. MacMillan said so! I could be wrong.
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yes curvature of the earth was mentioned in one of the article's I read yesterday.
 
zoogs said:
We're not talking about an object in freefall, though. So to model this as 2D projectile motion, you'll need to take the horizontal component into consideration (g is only relevant for the vertical component) as well. And you may want to assume air resistance.

Did the sniper actually talk about the curvature of the earth? That's so interesting. I didn't know it was this much, but I guess earth has a curvature of ~8 in/mi. Your projectile is traveling "in orbit", so to speak. g also varies by radial distance, although probably not materially over 16 inches (terrain elevation variation probably dominates...) I wonder how they distill all this modeling into intuitive guidelines for out in the field. The Coriolis effect actually seems much more relevant than curvature, and not just because Capt. MacMillan said so! I could be wrong.
Click to expand...
I think Mav is just talking about the bullet drop. Which is crazy... You would need to aim 490m above the target you are attempting to hit, 1,607 feet! That's nuts!
 
ZRod said:
zoogs said:
We're not talking about an object in freefall, though. So to model this as 2D projectile motion, you'll need to take the horizontal component into consideration (g is only relevant for the vertical component) as well. And you may want to assume air resistance.

Did the sniper actually talk about the curvature of the earth? That's so interesting. I didn't know it was this much, but I guess earth has a curvature of ~8 in/mi. Your projectile is traveling "in orbit", so to speak. g also varies by radial distance, although probably not materially over 16 inches (terrain elevation variation probably dominates...) I wonder how they distill all this modeling into intuitive guidelines for out in the field. The Coriolis effect actually seems much more relevant than curvature, and not just because Capt. MacMillan said so! I could be wrong.
Click to expand...
I think Mav is just talking about the bullet drop. Which is crazy... You would need to aim 490m above the target you are attempting to hit, 1,607 feet! That's nuts!
Click to expand...
Yes. The bullet would still "fall" 490 meters in 10 seconds. It doesn't matter if it's falling straight down or "falling" that far as it travels 2.2 miles horizontally.

 
That would exclude air resistance so it wouldn't be quite that far but still a crazy long ways.

 
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