Lil' Help here

[Husker-in-Manhattan]

I am in a discussion with a co-worker about how the conference champion is determined in a round robin format like that the Big 12 will be next year. If two teams finish with a 8-1 record in conference play, how is champion determined? I am saying it is head to head result. He is saying that both teams are awarded the conference title. He points to 1999 when Kstate and Nebraska both finished 7-1 in conference play and both teams got trophies.

[huKSer]

I am in a discussion with a co-worker about how the conference champion is determined in a round robin format like that the Big 12 will be next year. If two teams finish with a 8-1 record in conference play, how is champion determined? I am saying it is head to head result. He is saying that both teams are awarded the conference title. He points to 1999 when Kstate and Nebraska both finished 7-1 in conference play and both teams got trophies.

For the BCS bowl slot, both teams go. They merge the best players together and after 4 weeks they have a powerful fusion of awesomeness.

 

 

It's head to head, but the team that doesn't win gets a co-champion recognition participation ribbon.

[HuskerMack]

Well since they Haven't layed out the rules for the new format that the Big 12 will use next year it is going to be really hard to figure out unless they adopt the rules from the Big Ten. In which case

 

If there is a two-way tie, the winner of the game between the two will represent the conference. If the teams did not play each other, it is then based on overall winning percentage.

 

• If there is still a tie, the most recent team to earn a BCS automatic selection is eliminated.

 

• If three teams are tied and if one team defeated both of the others, that team is the representative.

 

• If two of the three teams defeated the third team, that team is eliminated and the remaining two teams revert to the two-team tie procedure.

 

• If two of the three did not play each other, the BCS representative is determined by winning percentage in the overall schedule. If all three have the same winning percentage, the most recent representative is eliminated and the other two revert to the two-team tie procedure.

 

• If four or more are tied ... if one team defeated each of the other three, then that team is the representative.

 

• If two of the four teams defeated each of the other two, those two are eliminated and the remaining two revert to the two-team tie procedure.

 

• If three of the four defeated the fourth, the fourth is eliminated, then it reverts to the three-team tie procedure.

 

• If two of the four did not play each other, the representative will be determined by overall winning percentage.

 

• If one of the four teams is eliminated through percentage, the remaining teams revert to three-team tie procedure.

 

• If all four have the same winning percentage, the most recently Big Ten representative is eliminated and the remaining three must go through the three-team tie procedure

[Husker-in-Manhattan]

Yes but in the Big 12 all teams will play each other. They do play a round robin in the PAC 10 and as recent as 2006 they have had "co-champs".